C++ - 为什么不能使用“const"限定符创建静态成员函数

C++ - Why static member function can#39;t be created with #39;const#39; qualifier(C++ - 为什么不能使用“const限定符创建静态成员函数)

问题描述

今天我遇到了一个问题.我需要一个 static 成员函数，const 不是必须的，而是更好的.但是，我的努力没有成功.有人能说出原因或方式吗?

Today I got a problem. I am in the need of a static member function, const is not a must but a better. But, I didn't succeed in my efforts. Can anybody say why or how?

推荐答案

当您将 const 限定符应用于非静态成员函数时，它会影响 this 指针.对于 C 类的 const 限定成员函数，this 指针的类型是 C const*，而对于不是const 限定，this 指针的类型为 C*.

When you apply the const qualifier to a nonstatic member function, it affects the this pointer. For a const-qualified member function of class C, the this pointer is of type C const*, whereas for a member function that is not const-qualified, the this pointer is of type C*.

静态成员函数没有 this 指针(此类函数不会在类的特定实例上调用)，因此静态成员函数的 const 限定没有任何意义.

A static member function does not have a this pointer (such a function is not called on a particular instance of a class), so const qualification of a static member function doesn't make any sense.

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