C++ 中的额外限定错误

extra qualification error in C++(C++ 中的额外限定错误)

问题描述

我有一个成员函数，定义如下:

Value JSONDeserializer::ParseValue(TDR 类型，const json_string& valueString);

当我编译源代码时，我得到:

class JSONDeserializer{值 JSONDeserializer::ParseValue(TDR 类型，const json_string& valueString);};

class JSONDeserializer{值解析值(TDR 类型，const json_string& valueString)；};

错误来自于JSONDeserializer::ParseValue 是一个限定名(具有命名空间限定的名称)，并且这样的名称在类中被禁止作为方法名.>

I have a member function that is defined as follows:

Value JSONDeserializer::ParseValue(TDR type, const json_string& valueString);

When I compile the source, I get:

error: extra qualification 'JSONDeserializer::' on member 'ParseValue'

What is this? How do I remove this error?

This is because you have the following code:

class JSONDeserializer
{
    Value JSONDeserializer::ParseValue(TDR type, const json_string& valueString);
};

This is not valid C++ but Visual Studio seems to accept it. You need to change it to the following code to be able to compile it with a standard compliant compiler (gcc is more compliant to the standard on this point).

class JSONDeserializer
{
    Value ParseValue(TDR type, const json_string& valueString);
};

The error come from the fact that JSONDeserializer::ParseValue is a qualified name (a name with a namespace qualification), and such a name is forbidden as a method name in a class.

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