无法访问派生模板类中模板基类的成员

Can#39;t access members of a Template base class within a derived template class(无法访问派生模板类中模板基类的成员)

问题描述

我有一个模板基类.可以说.

I have a template base class.Lets say.

template<class KeyF>
class Base 
{
  private:
   int member1;
   char member2;
   ....
};

我从上面的类派生了另一个类.

I derived another class from above class.

template<class KeyF>
class Derived : public Base<KeyF>
{
  public:
  void func1() {
    <accessing member1/member2>
  }

  ....
};

以上代码无法在 gcc 中编译.说 member1 不是 Derived 的成员.但是已经是从一个Base Class派生出来的，那为什么不能访问它的成员呢?

Above code doesn't compile in gcc. saying that member1 is not a member of Derived. But it is already derived from a Base Class, then why can't it access its member?

推荐答案

Base 中的成员是 private.您不能访问该类之外的类的私有成员(friend 除外).使它们protected，或protected getter.

Members in Base are private. You cannot access private members of class, outside of this class (except friend). Make them protected, or make protected getters.

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