boost自动链接如何做出选择?

How boost auto-linking makes choice?(boost自动链接如何做出选择?)

问题描述

当我使用 Visual Studio 2012 时，通过自动链接，我不需要手动添加 boost/POCO/python 库，它们会自动添加.如果我错过任何图书馆，我会收到这样的消息:

When I use Visual Studio 2012, with auto-linking, I don't need to add boost / POCO/ python libraries manually, they would be added automatically. And if I miss any library, I get message like that:

链接:致命错误 LNK1104:无法打开文件libboost_system-vc110-mt-1_55.lib"

LINK : fatal error LNK1104: cannot open file 'libboost_system-vc110-mt-1_55.lib'

但是它怎么知道我要链接哪个文件呢?也许我想动态链接，使用 boost_system-vs110-mt-1_55.lib，或者我想要一个带有 gd 或 sgd 的名字?

But how it knows which file I want to link? Maybe I want to link dynamically, using boost_system-vs110-mt-1_55.lib, or I want one with gd or sgd in name?

它是如何做出选择的?

问题是，我的程序在搜索系统、线程等时正在寻找 libboost_ ...(即静态)库，但它想要 python 的 boost_(即动态)，我只是不明白为什么?

Problem is, that my program is looking for libboost_ ... (i.e. static) libraries, when search for system, threads and etc, but it wants boost_ (i.e. dynamic) for python, and I just don't understand why?

推荐答案

Visual Studio 允许在源代码中使用 #pragma 指令来设置链接器选项.对于自动链接"，Boost 将这些 #pragma's 与现有的宏结合使用.

Visual Studio allows #pragma directives in the source code to set linker options. For "auto-linking", Boost uses these #pragma's in combination with existing macro's.

特别是，听起来您正在寻找 BOOST_ALL_DYN_LINK 宏.

In particular, it sounds like you are looking for the BOOST_ALL_DYN_LINK macro.

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