转义 C++ 字符串

Escaping a C++ string(转义 C++ 字符串)

问题描述

将 C++ std::string 转换为另一个 std::string 的最简单方法是什么，其中转义了所有不可打印的字符?

What's the easiest way to convert a C++ std::string to another std::string, which has all the unprintable characters escaped?

例如，对于两个字符的字符串[0x61,0x01]，结果字符串可能是ax01"或a%01".

For example, for the string of two characters [0x61,0x01], the result string might be "ax01" or "a%01".

推荐答案

看看 Boost 的 字符串算法库.您可以使用它的 is_print 分类器(连同它的操作符！重载)来挑选出不可打印的字符，它的 find_format() 函数可以用你想要的任何格式替换它们.

Take a look at the Boost's String Algorithm Library. You can use its is_print classifier (together with its operator! overload) to pick out nonprintable characters, and its find_format() functions can replace those with whatever formatting you wish.

#include <iostream>
#include <boost/format.hpp>
#include <boost/algorithm/string.hpp>

struct character_escaper
{
    template<typename FindResultT>
    std::string operator()(const FindResultT& Match) const
    {
        std::string s;
        for (typename FindResultT::const_iterator i = Match.begin();
             i != Match.end();
             i++) {
            s += str(boost::format("\x%02x") % static_cast<int>(*i));
        }
        return s;
    }
};

int main (int argc, char **argv)
{
    std::string s("ax01");
    boost::find_format_all(s, boost::token_finder(!boost::is_print()), character_escaper());
    std::cout << s << std::endl;
    return 0;
}

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