Why having const and non-const accessors?(为什么要有 const 和非 const 访问器?)
问题描述
Why do the STL containers define const and non-const versions of accessors ?
What is the advantage of defining const T& at(unsigned int i) const and T& at(unsigned int) and not only the non-const version ?
Because you wouldn't be able to call at on a const vector object.
If you only had the non-const version, the following:
const std::vector<int> x(10);
x.at(0);
would not compile. Having the const version makes this possible, and at the same time prevents you from actually changing what at returns - which is by contract, since the vector is const.
The non-const version can be called on a non-const object and allows you to modify the returned element, which is also valid because the vector isn't const.
const std::vector<int> x(10);
std::vector<int> y(10);
int z = x.at(0); //calls const version - is valid
x.at(0) = 10; //calls const version, returns const reference, invalid
z = y.at(0); //calls non-const version - is valid
y.at(0) = 10; //calls non-const version, returns non-const reference
//is valid
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本文标题为:为什么要有 const 和非 const 访问器?
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