将长二进制字符串转换为十六进制c#

Converting long string of binary to hex c#(将长二进制字符串转换为十六进制c#)

问题描述

我正在寻找一种将长二进制字符串转换为十六进制字符串的方法.

I'm looking for a way to convert a long string of binary to a hex string.

二进制字符串看起来像这样 "0110011010010111001001110101011100110100001101101000011001010110001101101011"

the binary string looks something like this "0110011010010111001001110101011100110100001101101000011001010110001101101011"

我尝试过使用

hex = String.Format("{0:X2}", Convert.ToUInt64(hex, 2));

但这只有在二进制字符串适合 Uint64 时才有效，如果字符串足够长则不会.

but that only works if the binary string fits into a Uint64 which if the string is long enough it won't.

还有其他方法可以将二进制字符串转换为十六进制吗?

is there another way to convert a string of binary into hex?

谢谢

推荐答案

我刚刚把这个搞砸了.或许你可以以此为起点……

I just knocked this up. Maybe you can use as a starting point...

public static string BinaryStringToHexString(string binary)
{
    if (string.IsNullOrEmpty(binary))
        return binary;

    StringBuilder result = new StringBuilder(binary.Length / 8 + 1);

    // TODO: check all 1's or 0's... throw otherwise

    int mod4Len = binary.Length % 8;
    if (mod4Len != 0)
    {
        // pad to length multiple of 8
        binary = binary.PadLeft(((binary.Length / 8) + 1) * 8, '0');
    }

    for (int i = 0; i < binary.Length; i += 8)
    {
        string eightBits = binary.Substring(i, 8);
        result.AppendFormat("{0:X2}", Convert.ToByte(eightBits, 2));
    }

    return result.ToString();
}

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