在C#中清除串口接收缓冲区

Clear serial port receive buffer in C#(在C#中清除串口接收缓冲区)

问题描述

只想知道如何在 C# 中清除我的串口的接收缓冲区.似乎接收缓冲区中的数据只是不断累积.例如，传入数据的流向是:[Data A]、[Data B]、[Data C].我想要的数据只是[Data C].我正在考虑这样做，当我收到 [Data A] 和 [Data B] 时，我会做一个清除缓冲区.仅当收到 [Data C] 时，我才继续处理.这是在 C# 中实现的方式吗?

Just want to know how do we clear the receive buffer of my serial port in C#. Seems like the data in the receive buffer just keep accumulating. For example, the flow of incoming data is: [Data A], [Data B], [Data C]. The data I want is just [Data C]. I'm thinking of doing like, when I receive [Data A] and [Data B], I do a clear buffer. Only when [Data C] is received, I continue process. Is this the way to do it in C#?

推荐答案

如果你使用的是 System.IO.Ports.SerialPort 那么你可以使用这两种方法:

If you are using the System.IO.Ports.SerialPort then you could use the two methods:

DiscardInBuffer() 和 DiscardOutBuffer() 刷新缓冲区.

如果你是从串口读取数据:

If you are reading the data from a serial port:

private void comPort_DataReceived(object sender, SerialDataReceivedEventArgs e)
{
    if (!this.Open) return; // We can't receive data if the port has already been closed.  This prevents IO Errors from being half way through receiving data when the port is closed.
    string line = String.empty;
    try
    {
        line = _SerialPort.ReadLine();
        line = line.Trim();
       //process your data if it is "DATA C", otherwise ignore
    }
    catch (IOException ex)
    {
        //process any errors
    }
}

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