从 Lucene Query 获取不同值的更快方法

Faster way to get distinct values from Lucene Query(从 Lucene Query 获取不同值的更快方法)

问题描述

目前我喜欢这样:

IndexSearcher searcher = new IndexSearcher(lucenePath);
Hits hits = searcher.Search(query);
Document doc;
List<string> companyNames = new List<string>();

for (int i = 0; i < hits.Length(); i++)
{
    doc = hits.Doc(i);
    companyNames.Add(doc.Get("companyName"));
}
searcher.Close();

companyNames = companyNames.Distinct<string>().Skip(offSet ?? 0).ToList();
return companyNames.Take(count??companyNames.Count()).ToList();

如您所见，我首先收集所有字段(数千个)然后区分它们，可能会跳过一些并取出一些.

As you can see, I first collect ALL the fields (several thousands) and then distinct them, possibly skip some and take some out.

我觉得应该有更好的方法来做到这一点.

I feel like there should be a better way to do this.

推荐答案

老实说，我不确定是否存在，因为 Lucene 不提供独特"的功能.我相信使用 SOLR 您可以使用构面搜索来实现这一点，但是如果您想在 Lucene 中实现这一点，则必须自己编写某种构面功能.所以只要你没有遇到任何性能问题，你应该没问题.

I'm not sure there is, honestly, as Lucene doesn't provide 'distinct' functionality. I believe with SOLR you can use a facet search to achieve this, but if you want this in Lucene, you'd have to write some sort of facet functionality yourself. So as long as you don't run into any performance issues, you should be ok this way.

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