Pivoting a table along with sum of column value when column type is nvarchar(当列类型为 nvarchar 时,将表与列值的总和一起旋转)
本文介绍了当列类型为 nvarchar 时,将表与列值的总和一起旋转的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个具有以下结构的表.我想转置它.
I have a table with following structure. I want to Transpose it.
BookId Status
----------------------
123A Perfect
123B Restore
123C Lost
123D Perfect
123A Perfect
123B Restore
123A Lost
123B Restore
我需要转置表看起来像这样.
I need the transpose table to look something like this.
输出
BookId Total Perfect Restore Lost
-----------------------------------------
123A 3 2 0 1
123B 3 0 3 0
123C 1 0 0 1
123D 1 1 0 0
我试过了
select
BookId,
sum('Perfect') as Perfect,
sum('Restore') as Restore
from
[dbo].[Orders]
group by
BookId
但由于这些是 nvarchar 值,sum 是无效的.我收到此错误
But as those are nvarchar values, sum is invalid. I am getting this error
我没有多少手在枢轴上.但尝试关注
I have not much hands on pivot. But tried following
select *
from
(select SellerAddress, ApplicationStatus
from [Farm_For_Books].[dbo].[Orders]) src
pivot
(sum(ApplicationStatus)
for SellerAddress in ([1], [2], [3])
) piv;
推荐答案
条件聚合可能会用到
with Orders( BookId, Status ) as
(
select '123A','Perfect' union all
select '123B','Restore' union all
select '123C','Lost' union all
select '123D','Perfect' union all
select '123A','Perfect' union all
select '123B','Restore' union all
select '123A','Lost' union all
select '123B','Restore'
)
select
BookId,
sum(1) as [Total],
sum(case when Status='Perfect' then 1 else 0 end ) as [Perfect],
sum(case when Status='Restore' then 1 else 0 end ) as [Restore],
sum(case when Status='Lost' then 1 else 0 end ) as [Lost]
from
[Orders]
group by BookId;
BookId Total Perfect Restore Lost
123A 3 2 0 1
123B 3 0 3 0
123C 1 0 0 1
123D 1 1 0 0
Rextester 演示
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