Oracle sql计算单列中不同值的实例

Oracle sql to count instances of different values in single column(Oracle sql计算单列中不同值的实例)

问题描述

我有一个带有状态列的表.我想要一个 Oracle sql 查询，它只会在一行中列出我在每个状态中的行数.例如，如果我的桌子是

I have a table with status column. I want an Oracle sql query which will list me count of rows in each status in only one row. for eg if my table is

Table A
Id       Status  Fkey
1         20      500
2         20      500  
3         30      501
4         40      501
5         30      502

输出应该是

Fkey     Count_status20     Count_status30    Count_status40
500        2                      0                 0
501        0                      1                 1

这里有点扭曲

Table B 
FKey TKey 
500   1001 
501   1001
502   1002 

现在输出应该是

TKey Count_status20     Count_status30    Count_status40 
1001     2                     1                    1 
1002     0                     1                    0

推荐答案

如果你使用的是Oracle 11g，那么你可以使用PIVOT函数:

If you are using Oracle 11g, then you can use the PIVOT function:

select *
from
(
  select tkey, status, 
    status as col
  from tableB b
  left join tableA a
    on a.fkey = b.fkey
) src
pivot
(
  count(status)
  for col in ('20' as Count_Status20, 
              '30' as Count_Status30,
              '40' as Count_Status40)
) piv;

请参阅 SQL Fiddle with Demo

如果你不使用Oracle11g，那么你可以使用带有CASE语句的聚合函数:

If you are not using Oracle11g, then you can use an aggregate function with a CASE statement:

select tkey, 
  count(case when status = 20 then 1 else null end) as Count_Status20,
  count(case when status = 30 then 1 else null end) as Count_Status30,
  count(case when status = 40 then 1 else null end) as Count_Status40
from tableB b
left join tableA a
  on b.fkey = a.fkey
group by tkey

请参阅 SQL Fiddle with Demo

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