java.sql.SQLException Parameter index out of range (1 gt; number of parameters, which is 0)(java.sql.SQLException 参数索引超出范围(1 参数个数,即 0))
问题描述
在验证了我选择的选择组合框后,我无法将其插入我的数据库中.Tomcat 报错:
After validation of select combo box which I have selected and I am not able to insert it in my database. Tomcat gives following error:
java.sql.SQLException:参数索引超出范围(1>参数个数,为0).
java.sql.SQLException: Parameter index out of range (1 > number of parameters, which is 0).
这是怎么引起的,我该如何解决?
How is this caused and how can I solve it?
推荐答案
当你在 PreparedStatement 上调用任何 setXxx() 方法时,你会得到这个错误,而SQL 查询字符串没有任何占位符 ? .
You will get this error when you call any of the setXxx() methods on PreparedStatement, while the SQL query string does not have any placeholders ? for this.
例如这是错误:
String sql = "INSERT INTO tablename (col1, col2, col3) VALUES (val1, val2, val3)";
// ...
preparedStatement = connection.prepareStatement(sql);
preparedStatement.setString(1, val1); // Fail.
preparedStatement.setString(2, val2);
preparedStatement.setString(3, val3);
您需要相应地修复 SQL 查询字符串以指定占位符.
You need to fix the SQL query string accordingly to specify the placeholders.
String sql = "INSERT INTO tablename (col1, col2, col3) VALUES (?, ?, ?)";
// ...
preparedStatement = connection.prepareStatement(sql);
preparedStatement.setString(1, val1);
preparedStatement.setString(2, val2);
preparedStatement.setString(3, val3);
注意参数索引以 1 开头,并且您确实不需要需要像这样引用这些占位符:
Note the parameter index starts with 1 and that you do not need to quote those placeholders like so:
String sql = "INSERT INTO tablename (col1, col2, col3) VALUES ('?', '?', '?')";
否则您仍然会得到相同的异常,因为 SQL 解析器会将它们解释为实际的字符串值,因此无法再找到占位符.
Otherwise you will still get the same exception, because the SQL parser will then interpret them as the actual string values and thus can't find the placeholders anymore.
- JDBC 教程 - 准备好的语句
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本文标题为:java.sql.SQLException 参数索引超出范围(1 > 参数个数,即 0)
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