如果它们完全相同，包括项目的顺序，则从列表

Remove duplicate tuples from a list if they are exactly the same including order of items(如果它们完全相同，包括项目的顺序，则从列表中删除重复的元组)

问题描述

我知道类似的问题已经在 Stack Overflow 上被问过很多次了，但我需要从列表中删除重复的元组，但不仅仅是它们的元素匹配，它们的元素必须按相同的顺序排列.换句话说，(4,3,5) 和 (3,4,5) 都将出现在输出中，而如果两者都有 (3,3,5) 和 (3,3,5)，只有一个会在输出中.

I know questions similar to this have been asked many, many times on Stack Overflow, but I need to remove duplicate tuples from a list, but not just if their elements match up, their elements have to be in the same order. In other words, (4,3,5) and (3,4,5) would both be present in the output, while if there were both(3,3,5) and (3,3,5), only one would be in the output.

具体来说，我的代码是:

Specifically, my code is:

import itertools

x = [1,1,1,2,2,2,3,3,3,4,4,5]
y = []

for x in itertools.combinations(x,3):
    y.append(x)
print(y)

其中的输出很长.例如，在输出中，应该同时存在 (1,2,1) 和 (1,1,2).但是应该只有一个(1,2,2).

of which the output is quite lengthy. For example, in the output, there should be both (1,2,1) and (1,1,2). But there should only be one (1,2,2).

推荐答案

set 会解决这个问题:

set will take care of that:

>>> a = [(1,2,2), (2,2,1), (1,2,2), (4,3,5), (3,3,5), (3,3,5), (3,4,5)]
>>> set(a)
set([(1, 2, 2), (2, 2, 1), (3, 4, 5), (3, 3, 5), (4, 3, 5)])
>>> list(set(a))
[(1, 2, 2), (2, 2, 1), (3, 4, 5), (3, 3, 5), (4, 3, 5)]
>>>

set 将仅删除 exact 个重复项.

set will remove only exact duplicates.

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