获取“位"；Python中的浮点数?

Get the quot;bitsquot; of a float in Python?(获取“位；Python中的浮点数?)

问题描述

我正在寻找与 Java 的 Float.floatToBits 等效的 Python.

I am looking for the Python equivalent of Java's Float.floatToBits.

我发现了这个 Python:获取 &操纵(作为整数)浮点数的位模式，但有人知道不那么复杂的方法吗?

I found this Python: obtain & manipulate (as integers) bit patterns of floats but does anyone know of a less complicated way?

推荐答案

Alex Martelli 在该问题中给出的答案非常简单——您可以将其简化为:

The answer that Alex Martelli gives in that question is really pretty simple -- you can reduce it to:

>>> import struct
>>> 
>>> 
>>> def floatToBits(f):
...     s = struct.pack('>f', f)
...     return struct.unpack('>l', s)[0]
...     
... 
>>> floatToBits(173.3125)
1127043072
>>> hex(_)
'0x432d5000'

一旦你将它作为一个整数，你可以执行任何其他你需要的操作.

Once you have it as an integer, you can perform any other manipulations you need to.

您可以将操作顺序颠倒为往返:

You can reverse the order of operations to round-trip:

>>> def bitsToFloat(b):
...     s = struct.pack('>l', b)
...     return struct.unpack('>f', s)[0]

>>> bitsToFloat(0x432d5000)
173.3125

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