Do python#39;s variable length arguments (*args) expand a generator at function call time?(python的可变长度参数(*args)是否在函数调用时扩展生成器?)
问题描述
考虑以下 Python 代码:
Consider the following Python code:
def f(*args):
for a in args:
pass
foo = ['foo', 'bar', 'baz']
# Python generator expressions FTW
gen = (f for f in foo)
f(*gen)
*args 会在调用时自动扩展生成器吗?换句话说,我是否在 f(*gen) 内对 gen 进行了两次迭代,一次是展开 *args,一次是对 args 进行迭代?还是生成器保持原始状态,而迭代只在 for 循环中发生一次?
Does *args automatically expand the generator at call-time? Put another way, am I iterating over gen twice within f(*gen), once to expand *args and once to iterate over args? Or is the generator preserved in pristine condition, while iteration only happens once during the for loop?
推荐答案
生成器在函数调用时展开,您可以轻松查看:
The generator is expanded at the time of the function call, as you can easily check:
def f(*args):
print(args)
foo = ['foo', 'bar', 'baz']
gen = (f for f in foo)
f(*gen)
将打印
('foo', 'bar', 'baz')
这篇关于python的可变长度参数(*args)是否在函数调用时扩展生成器?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持编程学习网!
本文标题为:python的可变长度参数(*args)是否在函数调用时扩展生成器?
基础教程推荐
- 尝试制作WhatsApp机器人 2022-01-01
- Discord.py 缺少必需的参数 2022-01-01
- pyserial - 可以从线程 a 写入串行端口,是否阻塞从线程 b 读取? 2022-01-01
- 将 x 轴刻度更改为自定义字符串 2022-01-01
- 使用生成器和迭代器时 Python 多循环失败 2022-01-01
- numpy float:比算术运算中内置的慢 10 倍? 2022-01-01
- 在 Celery 工作人员中捕获 Heroku SIGTERM 以优雅地关 2022-01-01
- 与常规 dict 相比,Python manager.dict() 非常慢 2022-01-01
- 由Python将MP3转换为MIDI(类型错误:无法加载插件:mtg-Melodia:Melodia) 2022-01-01
- 用 Python 编写 Fortran 无格式文件 2022-01-01
