正好需要 3 个参数(给定 4 个)

Takes exactly 3 arguments (4 given)(正好需要 3 个参数(给定 4 个))

问题描述

我正在重构代码以添加面向对象，我只是在测试代码.

i'm refactoring code in order to add object orientation and am just testing the code.

pattern = r"((([01]?[0-9]?[0-9]|2[0-4][0-9]|25[0-5])[ ([]?(.|dot)[ )]]?){3}([01]?[0-9]?[0-9]|2[0-4][0-9]|25[0-5]))"

class Lineobject(object):

        def __init__(self, pattern, line):
            self.ip = self.getip(self, pattern, line)

        def getip (self, pattern, line):
                for match in re.findall(pattern, line):
                    results = ''
                    ips = match[0]
                    usergeneratedblacklist.write(ips)
                    usergeneratedblacklist.write('
')
                    return ips

在实例化下面的类时，我遇到了一个奇怪的错误.getip() 正好需要 3 个参数(给定 4 个)，我不知道如何解决.

When instantiating the class below I am getting an odd error. That of getip() takes exactly 3 arguments (4 given) which i do not know how to resolve.

for theline in f:

    if "Failed password" in theline:

        lineclass = Lineobject(pattern, theline)

    else:
        pass

推荐答案

你给 self.getip() 四个参数，因为 Python 会自动添加第一个 self 参数绑定方法.表达式:

You are giving self.getip() four arguments because Python automatically adds in first self argument for bound methods. The expression:

self.getip(self, pattern, line)

结果:

getip(self, self, pattern, line)

这是四个个参数.

不要再传入self:

self.ip = self.getip(pattern, line)

在实例上查找方法的行为(通过self.getip)绑定为您处理第一个参数的方法.

The very act of looking up the method on the instance (via self.getip) binds the method to handle that first argument for you.

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