Python:计算字符串中的重叠子字符串

Python: Count overlapping substring in a string(Python:计算字符串中的重叠子字符串)

问题描述

假设我有 string = 'hannahannahskdjhannahannah' 并且我想计算字符串 hannah 出现的次数，我不能简单地使用 count，因为只有在每种情况下计算子字符串一次.

Say I have string = 'hannahannahskdjhannahannah' and I want to count the number of times the string hannah occurs, I can't simply use count, because that only counts the substring once in each case.

即.

我希望返回 4 但仅在使用 string.count('hannah')<在 pyCharm 中运行此命令时返回 2/p>

I am expecting to return 4 but only returns 2 when I run this in pyCharm with string.count('hannah')

推荐答案

您可以使用正在运行的索引来获取下一个事件:

You could use a running index to fetch the next occurance:

bla = 'hannahannahskdjhannahannah'
cnt = 0
idx = 0
while True:
    idx = bla.find('hannah', idx)
    if idx >= 0:
        cnt += 1
        idx += 1
    else:
        break
print(cnt)

给出:

>> 4

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