覆盖python中的静态方法

Overriding a static method in python(覆盖python中的静态方法)

问题描述

参考第一个答案这里关于python的绑定和未绑定方法，我有个问题:

Referring to the first answer about python's bound and unbound methods here, I have a question:

class Test:
    def method_one(self):
        print "Called method_one"
    @staticmethod
    def method_two():
        print "Called method_two"
    @staticmethod
    def method_three():
        Test.method_two()
class T2(Test):
    @staticmethod
    def method_two():
        print "T2"
a_test = Test()
a_test.method_one()
a_test.method_two()
a_test.method_three()
b_test = T2()
b_test.method_three()

产生输出:

Called method_one
Called method_two
Called method_two
Called method_two

有没有办法覆盖python中的静态方法?

Is there a way to override a static method in python?

我希望 b_test.method_three() 打印T2"，但它没有(而是打印Called method_two").

I expected b_test.method_three() to print "T2", but it doesn't (prints "Called method_two" instead).

推荐答案

在您使用的表单中，您明确指定要调用的类的静态 method_two.如果 method_three 是一个类方法，并且你调用了 cls.method_two，你会得到你想要的结果:

In the form that you are using there, you are explicitly specifying what class's static method_two to call. If method_three was a classmethod, and you called cls.method_two, you would get the results that you wanted:

class Test:
    def method_one(self):
        print "Called method_one"
    @staticmethod
    def method_two():
        print "Called method_two"
    @classmethod
    def method_three(cls):
        cls.method_two()

class T2(Test):
    @staticmethod
    def method_two():
        print "T2"

a_test = Test()
a_test.method_one()  # -> Called method_one
a_test.method_two()  # -> Called method_two
a_test.method_three()  # -> Called method_two

b_test = T2()
b_test.method_three()  # -> T2
Test.method_two()  # -> Called method_two
T2.method_three()  # -> T2

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