#include stdio.h#include string.hint main() {char s1[] = Beauty is in the eye of the beholder;
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#include <stdio.h>
#include <string.h>
int main() {
char s1[] = "Beauty is in the eye of the beholder";
char s2[] = "the";
int n = 0;
int m = 0;
int times = 0;
int len = strlen(s2); // contains the length of search string
while(s1[n] != '\0') {
if(s1[n] == s2[m]) { // if first character of search string matches
// keep on searching
while(s1[n] == s2[m] && s1[n] !='\0') {
n++;
m++;
}
// if we sequence of characters matching with the length of searched string
if(m == len && (s1[n] == ' ' || s1[n] == '\0')) {
// BINGO!! we find our search string.
times++;
}
} else { // if first character of search string DOES NOT match
while(s1[n] != ' ') { // Skip to next word
n++;
if(s1[n] == '\0')
break;
}
}
n++;
m=0; // reset the counter to start from first character of the search string.
}
if(times > 0) {
printf("'%s' appears %d time(s)\n", s2, times);
} else {
printf("'%s' does not appear in the sentence.\n", s2);
}
return 0;
}
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